Now, we can look at the probability of the Dealer getting it in the same suit as the player: In order to win, the player must already have a suited AJ Blackjack, so that removes an Ace from one of the suits and a Jack from one of the suits. Okay, so above is the probability of the player getting a suited AJ Blackjack.
Okay, so the player can get a Blackjack with the Ace-Jack or the Jack-Ace combo, there are 312 cards in six decks, 24 Aces, 24 Jacks: This is actually a fairly easy question, just separate the dealer and the player. But I assume (not sure) that we actually play a six-deck game.įirst of all, great question and welcome to WizardofVegas! I hope you stick around! My own calculations lead to something like 1:135000 for a single deck game. What is the probability of having a suited Ace-Jack? What is the probability that both dealer and player have a suited Ace-Jack? I recently started playing Blackjack in Zurich / Switzerland where there is a 'Progressive Jackpot' that pays when the player and the dealer both have a suited Ace-Jack (different suits for dealer and player allowed).
